Question

find the values for a and b of the function 2x^3+ax^2+bx+36 when local max is x=-4 and local min is x=5

Answer 1

find the derivative of the function and equate to zero

Answer 2

- is your first step

Answer 3

I think you can help her @cwrw238 .I just don't want to interfere.

Answer 4

not quite its 6x^2 + 2ax + b =0

Answer 5

ok hba ty

Answer 6

so its 6x^2 + 2ax + b = 0

now we know that zeros of this are -4 and 5
so if you plug in x = 5 and x = -4
into the above you will get 2 equations in a and b
solving this system will then give you the values of a and b

Answer 7

sorry gotta go now - theres plenty of capable guys to help you further