Question

where do I begin with proving tan y/(tan^2y-1)=1/(tan y- cot y)

Answer 1

tany/(tan^y-1) start by dividing both num and denom by tany
=1/((tan^y-1)/tany)
=1/(tany-(i/tany))
=1/(tany -coty)

Answer 2

Wow! Thanks. I keep forgetting to split (like in this case) the denominator into to fractions I can work with!