6.03] The three Math Idol judges have been eliminating contestants all day! The number of one-step equations and two-step equations who have been eliminated today is equal to 1070! If three times the number of one-step equations minus twice the number of two-step equations is equal to 110, how many one-step equations auditioned today?

900

620

520

450

Question

6.03] The three Math Idol judges have been eliminating contestants all day! The number of one-step equations and two-step equations who have been eliminated today is equal to 1070! If three times the number of one-step equations minus twice the number of two-step equations is equal to 110, how many one-step equations auditioned today?

900

620

520

450

anonymous · Answer

a + b = 1070         3a - 2b = 110     solve for a and b where "a" is the # of one-step equations and "b" is the # of two-step equations.

anonymous · Answer

I suggest you use substitution or elimination.

anonymous · Answer

umm

anonymous · Answer

idk what to doo

anonymous · Answer

Take your first equation, a + b = 1070       
Solve for "a", which is just subtracting "b" from each side
Put this value of "a" into the second equation..  That equation will have only one variable, "b".  Solve for "b".  Go back to your first equation with that value of "b" and get "a".

anonymous · Answer

i know that but how do i get the specific number

anonymous · Answer

That IS the way to get your specific number.  There is only one value for "a" and one value for "b" that will satisfy the two equations.  Just follow my steps.

anonymous · Answer

620?

anonymous · Answer

"a" is one-step and "b" is two-step.  You gave the answer for the # of two-step equations.  Your problem asks for the # of one-step equations.  You're almost there with your answer.  You're going in the right direction, though.

anonymous · Answer

its 520

anonymous · Answer

Check to see if you have the right answer by substituting those values for "a" and "b" back into the equations in my first post.