Express in impartial fractions

(12x^3 - 20x^2 + 31x - 49) / [ (x-1) (4x^2 + 9) ]

Is it in the form

A + B/(x-1) + C/(4x^2+9)

Or

A + B/(x-1) + Cx+D/(4x^2+9)

And why?

Thank you

Question

Express in impartial fractions 

(12x^3 - 20x^2 + 31x - 49) / [ (x-1) (4x^2 + 9) ] 

Is it in the form 

A + B/(x-1) + C/(4x^2+9)

Or

A + B/(x-1) + Cx+D/(4x^2+9)

And why? 


Thank you

hartnn · Answer

while separating for partial fraction, we see to it that degree of numerator is 1 less than degree of denominator.
so for 4x^2+9, which is quadratic., the numerator will be linear, ax+b.

anonymous · Answer

good

hartnn · Answer

you still have any doubts ? @1234abdc ??

anonymous · Answer

no I'm good :) 
thank you