Question

if the sum of the first 4 terms of arithmetic progressions p,he sum of the first 8 terms is q and he sum of the first 12 terms r,express 3p+r in terms of q.

Answer 1

u applied the formula ?
where are u stuck ??

Answer 2

how express 3p+r in terms of q

Answer 3

thats the question..
show your work.

Answer 4

1 min

Answer 5

3p+r = 6*[2a+3d] + 6*[2a+11d]
did u get this using formula ?

Answer 6

also, 4[2a+7d] = q
so, [2a+7d] = q/4

Answer 7

plz so this ....

Answer 8

what ?

Answer 9

plz solve this ??

Answer 10

did u get what i wrote above ?

Answer 11

3p+r = 6*[2a+3d] + 6*[2a+11d]
= 6*[2a+3d+2a+11d]
=6*[4a+14d]
= 6*[2(2a+7d)]
and 2a+7d was q/4
so,
3p+r = 6*[2(q/4)]
= 12q/4
=???

Answer 12

got that ^ ?

Answer 13

answer is 3p+r = 3q

Answer 14

yes.

Answer 15

12q/4=3q

Answer 16

thanks :) you are like my Sir

Answer 17

welcome ^_^