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OpenStudy (wwe123):
if the sum of the first 4 terms of arithmetic progressions p,he sum of the first 8 terms is q and he sum of the first 12 terms r,express 3p+r in terms of q.
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hartnn (hartnn):
u applied the formula ? where are u stuck ??
OpenStudy (wwe123):
how express 3p+r in terms of q
hartnn (hartnn):
thats the question.. show your work.
OpenStudy (wwe123):
1 min
hartnn (hartnn):
3p+r = 6*[2a+3d] + 6*[2a+11d] did u get this using formula ?
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hartnn (hartnn):
also, 4[2a+7d] = q so, [2a+7d] = q/4
OpenStudy (wwe123):
plz so this ....
hartnn (hartnn):
what ?
OpenStudy (wwe123):
plz solve this ??
hartnn (hartnn):
did u get what i wrote above ?
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hartnn (hartnn):
3p+r = 6*[2a+3d] + 6*[2a+11d] = 6*[2a+3d+2a+11d] =6*[4a+14d] = 6*[2(2a+7d)] and 2a+7d was q/4 so, 3p+r = 6*[2(q/4)] = 12q/4 =???
hartnn (hartnn):
got that ^ ?
OpenStudy (wwe123):
answer is 3p+r = 3q
hartnn (hartnn):
yes.
hartnn (hartnn):
12q/4=3q
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OpenStudy (wwe123):
thanks :) you are like my Sir
hartnn (hartnn):
welcome ^_^
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