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Mathematics 12 Online
OpenStudy (anonymous):

(_____)^2= (cscx-1)(cscx+1)

OpenStudy (anonymous):

is it cotx?

OpenStudy (anonymous):

ur r8

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

sin^2A+cos^2A=1 BUT divd by sin^2A both side ll be 1+cos^A/sin^2A=1/sin^2A THEN cos^2A/sin^2A=cot^2A SO ll be 1+cot^2A=cosec^2A THEN cot^2A=cosec^2A-1

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