Question

Solve the following logarithmic equation. log₃(x+4) = 2+log₃(x-20)

Answer 1

\[\log_{3}(x+4)=2+\log_{3}(x-20) \]

Answer 2

bring the log on the right over to the left side and rewrite as 1 log...
\(\large log_{3}(x+4)=2+\log_{3}(x-20)\)

\(\large log_{3}(x+4)-\log_{3}(x-20)=2\)

\(\large log_{3}(\frac{x+4}{x-20})=2\)

\(\large \frac{x+4}{x-20}=3^2 \)

can you take it from here?