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OpenStudy (anonymous):
Supose that 0 < f'(x) < 1/2 for all x-values. Show that f(-1) < f(1) < [2 + f(-1)]
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OpenStudy (anonymous):
inequality in integral: int0]-1 to 1 <intf']-1 to 1 <int 1/2 ]-1 to 1 0<f(1)-f(-1)<1/2(1--1)-> f(-1)<f(1)<2+f(-1)
OpenStudy (asnaseer):
hmmm - I think I can show this visually as follows: |dw:1353798197265:dw|
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