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Precalculus
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verify the Identity cos4u=cos^(2)(2u) - sin^(2)(2u)
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compare with standard identity cos(2x) = cos^2(x) - sin^2(x)
replace x with 2u
@cwrw238 so what is the answer?
Oh I thought those were 22's lolol, I'm glad you fixed it ambition :D I was really scratching my head over this one earlier.
As penguin guy said, this is the Double Angle Formula for Cosine. \[\huge \cos (2u)=\cos^2u-\sin^2u\] Let's apply this to our problem,\[\large \cos(4u) \quad = \quad \cos(2\cdot 2u)\]\[\large \cos(2\cdot 2u) \quad = \quad \cos^2(2u)-\sin^2(2u)\]
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ok so is there something else i have to do?
@zeepdrix
@zepdrix
no - xepdrix as done it all for you
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