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can someone help me solve this 2sin^2x + sinx-1 =0
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Treat it like a quadratic equation.
Do you know what I mean by that, @0213 ?
yes, i solved it, i got (2sinx-1)(sinx+1), then the answer for (2sinx-1) are 30 deg, and 150 deg, but i don't know how to get the answer for (sinx+1) since it solves to 270 deg (that is what the back of my book says it is).
If sin(x)+1=0 then sin(x)=-1, that occurs at 270º
oh, i get it. because on the graph of sin, at y=-1, x= 270. thank you
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No prob'
could you help me with another question?
Post it as a new question and I'll get to it when I can.
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