Question

Can someone see if I did these problems correct?
solve each equation on the interval [0.2pi)

1. 4sin^2x-3=0
Part I: Find two values of sinx that satisfy this equation
PartII: Solve each equation separately to get the full solution set, choosing only solutions on the interval [0, 2pi)
++++++++++++++++++++++++++++++
1.
4 sin^2 (x) - 3 = 0
4 sin^2 (x) = 3
sin^2 (x) = 3/4
sin (x) = +/- sqrt(3) / sqrt(4)
sin (x) = +/- sqrt(3) / 2
Answer to Part 1: sin(x) = +/- sqrt(3) / 2
sin(x) = sqrt(3) / 2
x = pi / 3
sin(x) = - sqrt(3) / 2
x = 5pi / 6
Answers to Part 2: x = pi / 3 or x =

Answer 1

5pi/6