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OpenStudy (anonymous):
Can someone see if I did these problems correct? solve each equation on the interval [0.2pi) 1. 4sin^2x-3=0 Part I: Find two values of sinx that satisfy this equation PartII: Solve each equation separately to get the full solution set, choosing only solutions on the interval [0, 2pi) ++++++++++++++++++++++++++++++ 1. 4 sin^2 (x) - 3 = 0 4 sin^2 (x) = 3 sin^2 (x) = 3/4 sin (x) = +/- sqrt(3) / sqrt(4) sin (x) = +/- sqrt(3) / 2 Answer to Part 1: sin(x) = +/- sqrt(3) / 2 sin(x) = sqrt(3) / 2 x = pi / 3 sin(x) = - sqrt(3) / 2 x = 5pi / 6 Answers to Part 2: x = pi / 3 or x =
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OpenStudy (anonymous):
5pi/6
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