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A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edges of two smaller cubes are 6 cm and 8 cm . Find the edge of the third smaller cube.(Assume that there is no loss of metal during melting).
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12*12*12=6*6*6+8*8*8+l*l*l
what???plz explain me
u hv to solve this equation
ok
the volume of larger cube is equal to the total volume of those small three cube
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\[V_{initial}=V_{final}\] \
ya u r righr
ok
do u wnt to get the solution of my equation
12*12*12=6*6*6+8*8*8+l*l*l |dw:1353831812338:dw|
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