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Algebra
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solve by elimination 5x=10+2y -4/3x+y=13/3
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5x -2y = 10 -4x +3y =13
5x=10+2y x=(10+2y)/5 Substitute this value of x in 2nd equation.
(3y-13)/4 =x in place of eq 1 and we get
-4/3*(10+2y)/5+y=13/3 (-40-8y)/15+15y/15=65/15 -40-8y+15y=65 7y=105 you may calculate y and then x from here. if you have any doubt, please tell.
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