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Mathematics 11 Online
OpenStudy (anonymous):

Find all solutions in the interval [0, 2π). sin^2x + sin x = 0

OpenStudy (cwrw238):

factoring sinx ( sinx + 1) = 0 sinx = 0 or -1

OpenStudy (anonymous):

wouldnt it be pi/3 and pi

OpenStudy (anonymous):

x=0

OpenStudy (anonymous):

yes i know o, pi but im not sure if the further one is pi/3

OpenStudy (anonymous):

how did you get pi/3

OpenStudy (anonymous):

i useed the identities

OpenStudy (cwrw238):

for sin x = -1 x = 270 degrees or 3pi/2

OpenStudy (anonymous):

just kidding i got 3pi/2

OpenStudy (anonymous):

LOL

OpenStudy (cwrw238):

lol

OpenStudy (anonymous):

i saw it right when i was typing thnks guys ":)

OpenStudy (cwrw238):

sin x = 0 for angle x = pi as well

OpenStudy (anonymous):

yes i know thanks <3

OpenStudy (anonymous):

and o ofcourse

OpenStudy (cwrw238):

so 3 solution x = 0, pi and 3pi/2

OpenStudy (anonymous):

yes thanks :)

OpenStudy (cwrw238):

yw

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