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Mathematics 23 Online
OpenStudy (anonymous):

Find the domain and range of 3y^2-12y+x-7=0

OpenStudy (cwrw238):

rearranging we get y = (1/3)[6 - sqrt3*sqrt(19-x)) sqrt(19-x) must be <= 0 so x < = 19 domain is x <=19 or in interval form (-infinity, 19]

OpenStudy (anonymous):

oh thanks

OpenStudy (cwrw238):

yw range is all real numbers

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