Question

find the vertex and axis of symmetry of the graph of the function: f(x)=x^2-8x

Answer 1

help

Answer 2

x = -b/(2a)

x = -(-8)/(2*1)

x = 4

So the axis of symmetry is 4

Now plug this in to get

f(x) = x^2 - 8x

f(4) = (4)^2 - 8(4)

f(4) = -16

So the vertex is (4, -16)