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Mathematics 8 Online
OpenStudy (anonymous):

(2x+1)^2+(2x+1)=0

OpenStudy (anonymous):

taking (2x+1) as common (2x+1)(2x+1+1)= 0 => either 2x+1 =0 OR 2x+2=0 so either x=-1/2 OR x=-1

OpenStudy (anonymous):

Thank you.

OpenStudy (anonymous):

no problemo !! :)

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