Solve the following system of equations.

2x + 2y + z = 10
3x – y + 3z = 10
2x + 3y – 2z = 6

Question

Solve the following system of equations. 

2x + 2y + z = 10 
3x – y + 3z = 10 
2x + 3y – 2z = 6

mathstudent55 · Answer

You can use elimination.
Eliminate z
Multiply entire first eq by 2 and add to eq 3:
4x + 4y + 2z = 10
2x + 3y - 2z = 6
-----------------
6x + 7y         = 16  call this eq. 4

Now multiply first eq by -3 and add to eq 2
-6x - 6y - 3z = -30
  3x -  y  + 3z =  10
-------------------
-3x  - 7y         = -20 call this eq. 5

Now solve eq 4 and eq 5 as a system of two equations.