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a2+b2=c2?
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If her hands were exactly at the same level as the boat, it would be approaching at 2ft/sec. The fact there's an angle means part of the effort is being used to move the rope UP towards her hands. The answer must be less than 2ft/sec.
The speed with which its being pulled is a vector in the same direction as the 25 feet of rope left. So you can use similar triangles. x/2=10/25 Next since what you actually want is the opposite side of the triangle sqrt(2^2-x^2)=1.833 is the real approaching speed.
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