the perimeter of a rectangle is 36 ft the length is 2 ft longer than the width / find the solution
write a system of linear equations and solve the resulting system
2x+2y = 2l +2w correct

Question

the perimeter of a rectangle is 36 ft the length is 2 ft longer than the width / find the solution
write a system of linear equations and solve the resulting system
2x+2y = 2l +2w correct

anonymous · Answer

l = length
w = width
Perimeter = 36

perimeter = 2l + 2w
l = w + 2

substitute
2(w+2) + 2w = 36
2w + 4 + 2w = 36
4w + 4 = 36
4w = 32
w = 8

l = 8 + 2
l = 10