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Chemistry 11 Online
OpenStudy (anonymous):

An unknown volume of laughing gas has a temperature of 325 K and a pressure of 0.5 kPa. The temperature is decreased to 320 K, the pressure is increased to 1.2 kPa, and the final volume of the gas is 48.0 L. What was the initial volume of the laughing gas?

OpenStudy (anonymous):

\[\frac{ P1V1 }{ T1 } = \frac{ P2V2 }{ T2 }\] Find V1...hope this helps

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