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Mathematics
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find the sum for the given arithmetic series:
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|dw:1353900255811:dw|
split it up into parts
\[\sum(2-3n)\] \[\sum2-\sum3n\] \[2\sum_{5}^{1}-3\sum_{1}^{5} n\] \[2(5)-3\frac{5(1+5)}{2}\]
lol, i got me 5 and 1 flipped around on that first sum
omg thank you so much! that was some big help right there :)
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your so smart lol
yep, another way to look at it, since the index is so small is like this: 2 − 3(1) 2 − 3(2) 2 − 3(3) 2 − 3(4) 2 − 3(5) ------- 2(5) -3(1+2+3+4+5)
oh wow that's much easier for me to understand. thanks
good luck ;)
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