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how can I create an equation of the line passing through (3, -1) (3,0) and (3, -3/4) ?
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you first need to pick two points....then you put the two points in to the equation y^2-y^1/x^2-x^1 so it should be 0+1/3-3, then you get your slope which is 1 Next you do the formula y-y1-mx-x1, so y+1=1x-3, then simplify to get y=1x-4
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thanks
your welcome
by the way the formula should be y-y1=mx-x1, just a typo
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got it, i forgot the formula. its been a while.
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