Question

Trying to solve quadratic equation x2-2x-13=0

Answer 1

you want the answer?

Answer 2

\[\frac{ +/- (b)\sqrt{b^2-4ac} }{ 2a }\]
ur values r
b=-2 a=1 c=-13
keep in mind, on the first b value with the plus and minus, the -2 becomes a positive 2.
inside the square root will look like 4-4(1)(-13)
and the denominator will look like 2(1).

Answer 3

the rest is up to u to solve

Answer 4

alright. I'll give you the answer.

Answer 5

1 +/- radical 14

Answer 6

yep that is right. i was just about to solve it XD. the set up i inputed is right?

Answer 7

yes just this part: