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Is my answer correct? ;) What value is added to both sides of the equation x2 - 8x = -10 in order to solve by completing the square? Answer: I know it would be 16 if the answer to the problem was -11, but in this case, the answer I got was "-8"
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what do you mean by "I know it would be 16 if the answer to the problem was -11"
I applied a certain step, and I figured I'd do the opposite for this problem....
and what step was that
a^2-2ab+b^2 = (a-b)^2 a = x => 2ab = 8x => b = 8x/2x => b = 4 => b^2 = 16 16 is to be added to both sides of the equation.
good, you can also use this shortcut x coefficient: -8 cut the x coefficient in half: -8/2 = 4 square that last result: 4^2 = 16
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thank you
yw
that makes it easier, thanks :)
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