Question

please check my answer? thanks!!!! ;)

Solve. 3x2 - 10x + 5 = 0

x = 2 _+_ sq root 20

Answer 1

\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]\[a=3,b=-10,c=5\]

Answer 2

ugh:(

Answer 3

plug and chug
\[x=\frac{10\pm\sqrt{100-4\times 3\times 5}}{6}\]

Answer 4

plug and chug hahaha ;)

Answer 5

what else can you do?
\[x=\frac{10\pm\sqrt{40}}{6}\]
\[x=\frac{10\pm2\sqrt{10}}{6}\]
\[x=\frac{5\pm\sqrt{10}}{3}\]

Answer 6

one second

Answer 7

k

Answer 8

x=2 sq root 10

Answer 9

over 6

Answer 10

dont forget the \(-b\) part in the numerator

Answer 11

and don't forget the \(\pm\) part, there are two answers

Answer 12

thank you ;)

Answer 13

yw

Answer 14

x = 5 + sq root 10/ 3? @satellite73

Answer 15

yes

Answer 16

also
\[\frac{5-\sqrt{10}}{3}\]