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What is the range of the graph of y = 5(x - 2)2 + 7?
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\[y = 5(x-2)^2 + 7\]
any guesses for this one?
Hint: Let x = 2
No guesses for this, I have NO idea how to do this
what @Hero said, reasoning that the first term \(5(x-2)^2\) is always greater than or equal to zero, because it is a square (any number squared is non - negative) the smallest value is therefor when \(x=2\) which makes the first term 0 and the whole thing is 7
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|dw:1353991542368:dw|
therefore the smallest it can be is 7, which is is if \(x=2\)
no, it is \(y\geq 7\)
reasoning is above
I'm going to write what you said down :) thank you
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yw
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