Question

Is it possible to determine the number of x-intercepts without graphing, y=-3(x-5)(x-5) + 20? why or why not

Answer 1

this is the same as \(y=-3(x-5)^2+20\) the parabola faces down and the vertex is \((5,20)\)
since the vertex is above the \(x\) axis, and since it opens down, it must cross the \(x\) axis at two places

Answer 2

Great thank you!

Answer 3

yw