Question

what are all the real zeroes
y=(x-12)^3-7

Answer 1

it would be nice if we could somehow get rid of that -12 and insert a cuberoot(7)

Answer 2

how do you do that

Answer 3

This is what I have but not sure if right
y=(x-12)-3 sgrt 7(x-12)^2+(x-12)3sgrt7+3sgrt49
x=12+3sgrt7

Answer 4

that is correct, yes; just make sure that 3sgrt is meant to be a cuberoot radical