Question

x^2-4 (x-2)
------ / ------
x-8 x-3

Answer 1

\[\frac{x^2-4}{x-8}\div\frac{x-2}{x-3}=\frac{x^2-4}{x-8}\times \frac{x-3}{x-2}\]
\[=\frac{(x-2)(x+2)(x-3)}{(x-8)(x-2)}\] then cancel the one common factor top and bottom

Answer 2

thank you ! (:

Answer 3

yw