Section 3.6#46
the formula
(y2-y1)=m(x2-x1)
the points are (6.25,0)=m(10,0)
(8,5-6,25)+m(10-0)
2.25/10 m=10/10
0.25=m
m=0.225 Your slope is correct. Now you need to write the equation of the line by using
y – y1 = m(x – x1)

where m = 0.225 and (x1, y1) is one of the given points.
i have to make an equation based on the information i cant do it i need help

Question

Section 3.6#46
the formula 
(y2-y1)=m(x2-x1)
the points are (6.25,0)=m(10,0)
(8,5-6,25)+m(10-0)
2.25/10 m=10/10
0.25=m
m=0.225  Your slope is correct.  Now you need to write the equation of the line by using 
y – y1 = m(x – x1)

 where m = 0.225 and (x1, y1) is one of the given points.
 i have to make an equation based on the information i cant do it i need help

anonymous · Answer

i am lost by what you wrote
what are the two points? 
it seems like they are $(6.25,0)$ and $(10,0)$ but that can't be right because then the slope would be $m=0$ not $m=0.225$

anonymous · Answer

name the two points and we can find the equation of the line

anonymous · Answer

let me go back and look at the question

anonymous · Answer

ok