Question

An object falls because of gravity at a rate of -980 cm/s^2 (- sign is indicative of a downward direction) for 10. seconds. If it starts from rest (Vo = 0) and its position starts from Do= 0.0, where is it 10. seconds later?

Answer 1

\[ S=Vt + (1/2)at^{2}\]
V=0, t=10, a = -980cm/sec.sec
S= -490 meters

Answer 2

Thanks...! :)