Question

Solve the following system of equations.

x + 3y + 2z = –16
2x – y + 2z = –15
2x – 2y – z = 1

Answer 1

x=-3
y=-1
z=-5

Answer 2

First step is eliminate the Z

x + 3y + 2z = -16
2x - y + 2z = -15
------------------------------ (-)
-x + 4y = -1 ----------------------------------------… (1)

x + 3y + 2z = -16 x + 3y + 2z = -16
2x - 2y - z = 1 x2 4x - 4y - 2z = 2
---------------------------------- (+)
5x- y = - 14 ----------------------------------------… (2)

Answer 3

Second step is eliminate the Y

(1) and (2)
-x + 4y = -1 -x + 4y = -1
5x - y = -14 x 4 20x - 4y = -56
------------------------ (+)
-19x = -57
x = 57/19 ----------------------------------------… (3)

After get the X value, put in equation (2) to get the Y value

5x - y = -14
- y = - 14 -5x
y = 14 + 5 x

Next after you get the X and Y, put in your first equation

x + 3y + 2z = -16
2z = -16 -x-3y
z = -8 - 1/2 x - 3/2y

then you get the Z....

sorry not much time to calculate the rest for you :)

Answer 4

thanks you guys c: