Question

what is the radius of x^2+y^2-12x-6y-4=0

Answer 1

This is the general equation for circle,
eqn
x^2+y^2+2gx+2fy+c=0
centre: (-g, -f), in this case the centre is (-6, 3)
radius: (g^2+f^2-c)^1/2, in this case the radius is 7.
To draw the
raph paper of scale 10 small divisions=1cm), and at a distance of 7cm draw a circle.

Answer 2

so radius would be 7?

Answer 3

Yes