Question

What are the coordinates of the center of the circle x^2+y^2-12x-6y-4=0

Answer 1

i think it may -6,3 but not sure

Answer 2

do you know how to complete the square

\[x^2 - 12x +y^2 - 6y = 4\]

Answer 3

ik that the centre is: (-g, -f)

Answer 4

all you need to do to make certain is complete the square to both x and y

\[x^2 -12x + (12/2)^2 + y^2 -6y + (6/2)^2 = 4 +(12/2)^2 + (6/2)^2\]

factorising the terms in x and y, which are now perfect squares, will give the centre and radius