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Mathematics 14 Online
OpenStudy (anonymous):

can anyone help me prove sin2x cscx = 2cosx?

OpenStudy (anonymous):

sin2x = 2sinxcosx, and cscx =1/sinx, so.. 2sinxcosx*1/sinx

OpenStudy (anonymous):

canceling sinx gives.... 2cosx=2cosx

OpenStudy (anonymous):

omg thank you soo much ive been stuck on this for so long

OpenStudy (anonymous):

glad to help :)

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