Question

http://media01.owotw.com/o_alg02_2011/6/img_exam_45.gif

Answer 1

add and simplify

Answer 2

@jim_thompson5910

Answer 3

help please

Answer 4

\[\Large x + \frac{2x}{x+1}\]


\[\Large \frac{x}{1} + \frac{2x}{x+1}\]


\[\Large \frac{x(x+1)}{1(x+1)} + \frac{2x}{x+1}\]


\[\Large \frac{x(x+1)}{x+1} + \frac{2x}{x+1}\]


\[\Large \frac{x(x+1)+2x}{x+1}\]


\[\Large \frac{x^2+x+2x}{x+1}\]


\[\Large \frac{x^2+3x}{x+1}\]

Answer 5

http://media01.owotw.com/o_alg02_2011/6/img_exam_45b.gif

Answer 6

is this the answer

Answer 7

ok so you just have to factor x^3 + 3x to get x(x+3)

Answer 8

yes

Answer 9

so yes they are the same