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Trigonometry
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Find the exact solutions. Half or double angle identity?
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\[3+ \cos(2x) = 2\sin(x) for 0 \le x \le 2\pi\]
Change cos2x to 1-2sin^2x Then move everything to one side and you will find you have a quadratic
I did that and found that I could not factor: \[2(\sin ^{2}(x)\sin(x)-2)\] Am I being dumb and missing something here?
Is there a minus sign in the middle there?
The sines shouldnt be multiplied together, the equation should form a quadratic
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Sorry, \[-2(\sin ^{2}(x) + \sin(x) -2)\]
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