Question

log2(2x-3)=-1

Answer 1

\[\log _{2}2x-3=-1\]

?

Answer 2

yes

Answer 3

I put 2 as the base for the right side of the equation and got stuck.

Answer 4

Take the base, 2, and do

\[2^{\log _{2}2x-3}=2^{-1}\]

Answer 5

Ah, the log and exponential cancel out on the left so it leaves you with

\[2x-3=2^{-1}\]

Answer 6

so 2x-3=1/2

Answer 7

?

Answer 8

Correct. can you solve it from here?

Answer 9

I believe so is the answer 7/4?

Answer 10

Correct

Answer 11

Thank You!

Answer 12

You're welcome