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Mathematics 17 Online
OpenStudy (anonymous):

can someone please remind me how to find "X" in this matrix...http://i45.tinypic.com/2d2c9br.jpg

OpenStudy (anonymous):

@KonradZuse @asnaseer

OpenStudy (anonymous):

let AX=B.....where A and B you know....find A inverse and then X=(inverse of A)B

OpenStudy (sirm3d):

here's a quick solution to the inverse of a 2x2 matrix A \[\large A=\left[\begin{matrix}a & b \\ c & d\end{matrix}\right]\]\[\large A^{-1} = \left[\begin{matrix}\frac{ d }{ ad-bc } & \frac{ -b }{ ad-bc } \\ \frac{ -c }{ ad-bc } & \frac{ a }{ ad-bc }\end{matrix}\right]\]

OpenStudy (sirm3d):

in \[\large AX=B, \\ \large X=A^{-1}B\]

OpenStudy (anonymous):

thanks @sirm3d and @stgreen

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