Question

Find the solution of the initial value problem.
(dy/dx) = 6x^2 + 6x ;
y(2) = 14

Answer 1

y=2x^3 + 3x^2 -14

Answer 2

you integrate and you get y(x)=y=2x^3 + 3x^2 +c
Now, to find C, you plug in 2 into the new equation and set it equal to 14. Then, you solve for c. So the Final equation is y=2x^3 + 3x^2 -14

Hope that helps

Answer 3

thanks guys ;)