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Mathematics 10 Online
OpenStudy (anonymous):

@privetek Find the value of x and y.

OpenStudy (anonymous):

number 7

OpenStudy (anonymous):

@privetek im done now number 7

OpenStudy (anonymous):

@privetek ur gone :(

OpenStudy (anonymous):

hey.. i'm still here.. i'll try helping you out

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

it's the Pythagorean theorem.. y^2 = [3sqrt(2)]^2 + [3sqrt(2)]^2 y^2 = 2 [3sqrt(2)]^2 y = sqrt[ 2 [3sqrt(2)]^2 ] y = 3sqrt2 * sqrt2 y = 3*2 = 6 solving for x its the 45-45-90 special right triangle.. |dw:1354141631254:dw|

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