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Simplify and write in radical form: ((x^3 * y^-2) / xy)^-(1/5)
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\[(x ^{3}y ^{-2}/xy)^{-1/5}\] this equation?
Yes, that's the one.
Take it one step at a time:\[(\frac{x^{3}}{y^{2}}\frac{1}{xy})^{\frac{-1}{5}}\]\[(\frac{x^{3}}{xy^{3}})^{\frac{-1}{5}}\]\[(\frac{x^{2}}{y^{3}})^{\frac{-1}{5}}\]\[(\frac{y^{3}}{x^{2}})^{\frac{1}{5}}\]\[\sqrt[5]{\frac{y^{3}}{x^{2}}}\]
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