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an arrow is fired directly horizontal off a cliff that is 10 meters tall with a velocity of 65.5m/s. A. How long is the arrow in the air? B. What is the range of the arrow?
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\[\Delta y= -10 = -\frac{ g t^2 }{ 2 }\]
find t and use in \[\Delta x = 65.5t\]
\[\Delta y = \frac{ -1 }{ 2 } (g) (t^2)\]
\[\Delta x = Vx(t)\]
\[g=9.8\]
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yes
which one is x and which one is y?
i can solve it
r u rhere
h=0.5gt*t or, 10=0.5*9.8*t*t or, t=1.4 sec
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range R=65.5*1.4=91.7m
if u need explanation then ask me when u r online
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