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Physics 17 Online
OpenStudy (anonymous):

A force of 105N is applied horizontally to a 20.0kg box to move it across a horizontal floor. If the box has an acceleration of 3.00m/s^2, find its coefficient of friction.

OpenStudy (shamim):

coefficient of friction=(105-60)/(20*9.8)=0.22959

OpenStudy (shamim):

if u need explanation then i will shaw the whole story

OpenStudy (shamim):

i think u r now offline

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