Question

the line contains the point (2,-3) and has a slope of (-1/2). Can anyone please help me with this? I need to write an equation in slope-intercept form.

Answer 1

y-y1=m(x-x1) where (x1,y1) is the any point on the line and m is its slope...
so y+3=(-1/2)(x-2)
2y+6=-x+2
2y=-x-4
y=(-1/2)x-2
slope=-1/2
y intercept = -2

Answer 2

Thanks, I made my mistake on the y+3=(-1/2)(x-2), I wrote y-3. thanks again

Answer 3

no problem :)