can someone please help on these questions??
i have a math test and trying to study for tomorrow
2sinAcosA=squareroot of 3/2
tan(thetha) - tan(15degrees) divide by
1+tan(thetha)tan(15degrees) =1
1-cosx/sinx = squareroot of 3
for these i have to find the genral solution in terms of 360*n 2*pi*n and find the particular values of x
please any help will be greatly appreciated!!

Question

can someone please help on these questions??
i have a math test and trying to study for tomorrow
2sinAcosA=squareroot of 3/2
tan(thetha) - tan(15degrees) divide by 
1+tan(thetha)tan(15degrees) =1
1-cosx/sinx = squareroot of 3
for these i have to find the genral solution in terms of 360*n 2*pi*n and find the particular values of x 
please any help will be greatly appreciated!!

anonymous · Answer

2sinAcosA   =    √3 /2
    sin2A        =    sin 60
   ->     A        =          30° + K360°

anonymous · Answer

( tan θ - tan15° ) /  ( 1 - tanθ tan15 )    =    1
                                       tan ( θ - 15 )    =     tan 45°
                                  ->          θ              =     60°  +  k180°