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can x^3 + 8 be factorised? if so it is using a3 + b3 = (a + b)(a2 – ab + b2)?
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(x-2)(x^2 + 2x + 4)
But the question is x^3 + 8 not minus?
yes, and your are correct,a=x and b=2
*you
Well i was looking to find it in factored from not the answer
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form*
yeah, i didn't give any answer... factored form will be ... ?
x^3+2^3 = (...+...)(....-....+...)
Well the formula are as follows, \[a^3 + b^3 = (a + b)(a^2 – ab + b^2)\] \[a^3 - b^3 = (a - b)(a^2 + ab + b^2)\]
(x+2)(x^2- 2 + 4) Is this right?
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the 2nd term in 2nd bracket is incorrect.
i mean 2x opps (x+2)(x^2- 2x + 4)
yeah, now correct....
Yeah right
thanks
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Your'e welcome.
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