Question

LIMITS

Answer 1

\[\lim_{x \rightarrow \infty } \frac{\sqrt{a+x}-\sqrt{a}}{\sqrt{a(a+x)}} \]

Answer 2

@cwrw238 @hartnn

Answer 3

sorry! the limit tends to 0 not infinity!

Answer 4

then directly put x=0

Answer 5

indeterminate

Answer 6

sure ?

Answer 7

i get 0

Answer 8

:/..
this has been posted before too..and answer isnt 0
http://openstudy.com/users/dls#/updates/506492ace4b0583d5cd3e7d5

Answer 9

PUT x=0 , u don't get indeterminate form... and u get 0...try again...

Answer 10

i meant 0 only,i wrote indeterminate by mistake,that isnt the answer

Answer 11

u probably seeing answer to other question....

Answer 12

nope!

Answer 13

wolf.
http://www.wolframalpha.com/input/?i=limit+x-%3E0+%28sqrt%28a%2Bx%29-sqrt+a%29%2F+%28sqrt+%28a*%28a%2Bx%29%29%29%29

Answer 14

http://www.wolframalpha.com/input/?i=limit+x-%3E0+%28%28sqrt%28a%2Bx%29%29-sqrt%28a%29%29%2F%28x%28sqrt%28a%28a%2Bx%29%29

Answer 15

lol

Answer 16

u didn't write x in denom. -_-

Answer 17

oh !!! hw do i apologize :/

Answer 18

so ques is checked now! :p

Answer 19

u got
\(\frac{x}{\sqrt{a(a+x)}(\sqrt{a+x} +{\sqrt{a}})}\)
actually its
\(\frac{x}{x\sqrt{a(a+x)}(\sqrt{a+x} +{\sqrt{a}})}\)
x cancels out.

Answer 20

yeah okay

Answer 21

then u can put x=0

Answer 22

okay thanks!