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Find the value of sec Θ for the angle shown.
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sec Θ = \[\frac{ 7\sqrt{85} }{ 85 }\] sec Θ = \[\frac{ 6 }{ 7 }\] sec Θ = \[\frac{ 7}{ 6 }\] sec Θ = \[\frac{ \sqrt{85} }{ 7 }\]
find the hypotenuse of the right triangle secant will be the length of the hypotenuse divided by the length of the adjacent side (which is 7)
how do i find the hypotenuse
you use pythagoras' theorem...
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a^2+b^2=c^2
thats the theorem
so the answer would be \[\frac{ \sqrt{85} }{ 7 }\]
makes sense to me
ok thank you!
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